Removing date from string

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I have strings like:

  2022-02-11_9051b

  2022-02-11S9051b

  S9051D2022-02-11

I want to extract the date, which is always in format YYY-MM-DD. I can use grepstr to check whether the string contains a date in this format. But how can I find the location in the string of the date, or somehow extract it? greplist won't cover the cases where the separator is not something standard like "_". And I can't use strSearch because I don't know of a wildcard character specifically for digits. Or maybe it's possible to search for a digit using one of the str functions?

 

This function will give you the date from any string if the date is in the format YYYY-MM-DD:

Function/S ExtractDate(string in)
    string out
    SplitString/E=("([0-9]{4}-[0-9]{2}-[0-9]{2})") in, out
    return out
End

Example:

•print ExtractDate("S9051D2022-02-11test")
  2022-02-11

 

February 17, 2024 at 01:39 pm - Permalink