Elliptic integrals
amtravco
It would be nice to have complete and incomplete elliptic integrals of the first and second kind available.
It would be nice to have complete and incomplete elliptic integrals of the first and second kind available.
OK, I've figured out that
E(k) = (pi/2)*hyperG2F1(-1/2, 1/2, 1, k^2)
and
K(k) = (pi/2)*hyperG2F1(1/2, 1/2, 1, k^2).
Maybe not the most efficient implementation, but it will do the job.
April 18, 2020 at 06:29 pm - Permalink