Question on setting up a fitting function
hegedus
The independent experimental variable is current, I
The dependent measured variable is voltage, V
The form of the solution is
I = J1(exp(k(V-RsI))-1) + J2(exp(k/2(V-RsI))-1) + (V-RsI)/Rsh
we need to solve for J1, J2, Rs, and Rsh. k is a known value. Note that I appears in both sides of the equation. How would I set up the fitting function? A twist is that while experimentally the current, I, is set and Voltage, V, is measured in graphing V is on the X axis. I have started the discussion that fitting X by Y versus Y by X yield different answers.
Andy Hegedus
Principal MTS
Alta Devices
What if a change the problem a bit:
Change
I = J1(exp(k(V-RsI))-1) + J2(exp(k/2(V-RsI))-1) + (V-RsI)/Rsh
to
g(V,I) = J1(exp(k(V-RsI))-1) + J2(exp(k/2(V-RsI))-1) + (V-RsI)/Rsh -I
where the new function g(V,I) has a value of 0 (zero) at all the points. I can then run a multidimensional fit using V and I as input variables. Does this fly or is the error minimization thrown off?
Andy Hegedus
Principal MTS
Alta Devices
November 20, 2009 at 02:55 pm - Permalink
Another approach would be FuncFit/ODR=3 to do an implicit fit. Read about it:
DisplayHelpTopic "Fitting Implicit Functions"
John Weeks
WaveMetrics, Inc.
support@wavemetrics.com
November 20, 2009 at 03:15 pm - Permalink